HELP,HELP,HELP,HELP
How can you tell that cobalt(II) iodide is binary ionic compound formed by a transition metal with more than ionic charge? Thanx in Advance form jeff
Cobalt(II) chloride tells you it is binary (composed of two different atoms), cobalt and iodine; compare the electronegativity of Co and I to determine if it is ionic; cobalt is in the 3d (period 3) of the periodic table and that is the 3d transition series of metals. I don't know what you mean by more than ionic charge>
To determine if cobalt(II) iodide is a binary ionic compound formed by a transition metal with more than ionic charge, you can follow these steps:
1. Identify the elements present: In this case, we have cobalt (Co) and iodine (I).
2. Determine the charges of the ions: Cobalt(II) would have a +2 charge since it is in the 2+ oxidation state, and iodine will have a -1 charge since it usually forms an ion with a single negative charge when it reacts.
3. Check the electronegativity difference: Ionic compounds are formed when there is a large difference in electronegativity between the atoms involved. Electronegativity is the tendency of an atom to attract electrons towards itself. To determine the difference, you can compare the electronegativity values of cobalt and iodine. Cobalt has an electronegativity of 1.88, while iodine has an electronegativity of 2.66. The difference in electronegativity is 2.66 - 1.88 = 0.78, which indicates an ionic bond.
4. Consider the position of cobalt in the periodic table: Cobalt is a transition metal and is located in the d-block, specifically in the 3d transition series. Transition metals can form multiple charged ions, so cobalt can have more than one possible ionic charge. In this case, it is cobalt(II), indicating a +2 charge.
Based on these observations, we can conclude that cobalt(II) iodide is a binary ionic compound formed by a transition metal (cobalt) with a +2 ionic charge.