an airplane was moving with a velocity equal to 150 mph when the velocity was increased with uniform acceleration to 300 mph in 5 min. Calculate the number of miles the airplane traveled during that interval
V = Vo + a*t
a = (V-Vo)/t
a=(300-150)/(1/12)h=1800=1800 mi/h^2
V^2 = Vo^2 + 2a*d
d = (V^2-Vo^2)/2a.
d = (90000-22500)/3600 = 18.75 Miles.