Consider this molecular-level representation of a gas.

5 orange
6 green---> 3 pairs
6 blue

If the partial pressure of a diatomic gas is .750 atm, what is the total pressure?

that partial pressure of each gas is proportional to the moles of each gas, in this case, atoms. If blue, green, and orange have the same relative mass, then

moles orange=5
moles blue=5
moles green=3

total pressure=P
green pressure=3P/13
solve for P from given .750
http://chemistry.about.com/od/chemistryfaqs/f/What-Is-Daltons-Law-Of-Partial-Pressures.htm

So would it be (3)(.750)/13?

.1731 would be the answer?

To determine the total pressure, we need to find the partial pressures of all the gases in the mixture and then add them together.

In the given molecular-level representation, we have a diatomic gas with 3 pairs of green spheres. Let's assume each pair of green spheres represents one molecule of the diatomic gas.

From the given information, we know that the partial pressure of the diatomic gas is 0.750 atm. Therefore, we can conclude that the partial pressure of each pair of green spheres is also 0.750 atm.

Now, since we have 3 pairs of green spheres, we can calculate the total pressure by multiplying the partial pressure of each pair by the number of pairs and adding it to the pressure contributed by the other gases.

For the total pressure calculation, we need to consider the contribution of each type of gas to the total pressure. From the molecular-level representation, we have:

- 5 orange spheres: We don't know their contribution to the pressure, so we'll ignore them for now.
- 3 pairs of green spheres: Each pair contributes 0.750 atm, so the total contribution is 3 * 0.750 atm = 2.250 atm.
- 6 blue spheres: We don't know their contribution to the pressure, so we'll ignore them for now.

Now, we can add up the partial pressures to find the total pressure:

Total pressure = Pressure from green spheres + Pressure from other gases

Total pressure = 2.250 atm + Pressure from other gases

To find the pressure from other gases, we need to consider the pressure contribution from the 5 orange spheres and 6 blue spheres.

Unfortunately, we don't have enough information about the orange and blue spheres to determine their contribution to the pressure, so we cannot calculate the exact value of the total pressure using the given information.