No clue how to solve this.
If you have performed a linear regression of data that ranges from 1-10 and has a y=2x+5, what is the extrapolated value for y at 11
this is easier than you are trying to envision it. You have a bunch of data, and you have found that the straight line of best fit is
y = 2x+5
You have no real formula that produces every data point in the interval [1,10], but this line does as well as you can.
So, now you have a line which closely fits all observed data. To extrapolate to other data, all you can do is estimate based on your calculations so far.
y(11) = 27
Thanks
To find the extrapolated value for y at 11 using the given linear regression equation, you can follow these steps:
Step 1: Determine the equation of the line in the form y = mx + b, where m is the slope and b is the y-intercept.
Given equation: y = 2x + 5
Here, the slope (m) is 2 and the y-intercept (b) is 5.
Step 2: Substitute the value of x as 11 into the equation.
y = 2x + 5
y = 2(11) + 5
Step 3: Calculate the value.
y = 22 + 5
y = 27
Therefore, the extrapolated value for y at 11, using the given linear regression equation y = 2x + 5, is 27.
To find the extrapolated value for y at 11, you can use the equation of the linear regression line, which is y = mx + b. In this case, the line is given by y = 2x + 5, where m is the slope of the line (2) and b is the y-intercept (5).
To find the value of y at x = 11, you can substitute x = 11 into the equation:
y = 2x + 5
y = 2(11) + 5
y = 22 + 5
y = 27
So the extrapolated value for y at 11 is 27.