math

write 3x^2 +8x-25 in the form a(x+h)^2,where a,h and k are real numbers

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asked by richard
  1. That expression is not a perfect square. You would have to add a constant. Maybe that is the "k" that you left out

    3x^2 +8x -25 = 3(x^2 + 8x/3 -25/3)
    = 3(x^2 + 8x/3 + 16/9) -25 - 48/9
    = 3(x + 4/3)^2 - 123/9

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    posted by drwls

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