A ball is thrown upward with an initial velocity of 14 m/s. At what time does the ball reach the high point in its flight? (Use the approximate value of g = 10 m/s2 and remember that the velocity is equal to zero at the high point.)
apply formula
v=u-gt
v=0
u=14
g=10
then t=1.4s
To find the time at which the ball reaches its high point, we can use the equations of motion. In this case, since the initial velocity is given and the final velocity at the high point is zero, we can use the following equation:
v = u + gt
Where:
v = final velocity (0 m/s at the high point)
u = initial velocity (14 m/s)
g = acceleration due to gravity (approximately 10 m/s^2)
t = time
We can rearrange the equation to solve for the time (t):
t = (v - u) / g
Substituting the values:
t = (0 - 14) / 10
t = -14 / 10
t = -1.4
The negative sign indicates that the ball will reach its high point 1.4 seconds after it was thrown. However, since time cannot be negative, we discard the negative sign. Therefore, the ball reaches its high point approximately 1.4 seconds after it was thrown.
v=v₀-gt
v=0
t=v₀/g=14/10=1.4 s