David's clock ticks once for every two of Phil's clock ticks. How fast is Phil
moving by David?
To determine how fast Phil is moving relative to David, we need to compare the rates at which their clocks tick.
Let's denote the rate at which David's clock ticks as "D" and the rate at which Phil's clock ticks as "P".
According to the information given, David's clock ticks once for every two of Phil's clock ticks. This can be expressed as:
D = (1/2)P
Now, we need to find the value of P.
To do this, we can rearrange the equation:
P = 2D
Here, the value of P represents Phil's rate, which is twice as fast as David's rate. Therefore, Phil is moving at a rate that is twice as fast as David.