Two balls are drawn from a bag with 4 black balls and 2 white balls. Find th probability distribution got drawing 2 black balls.
Not distribution.
Without replacement,
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
first black ball = 4/6
second black ball = 3/5
To find the probability distribution of drawing 2 black balls, we need to calculate the probability of each possible outcome.
First, let's determine the total number of balls in the bag: 4 black balls + 2 white balls = 6 balls.
Next, let's calculate the probability of drawing the first black ball. Since there are 4 black balls out of 6 total balls, the probability of drawing the first black ball is 4/6.
After drawing the first black ball, there are now 3 black balls remaining out of 5 total balls. Therefore, the probability of drawing the second black ball, given that the first ball was black, is 3/5.
To find the probability of drawing 2 black balls, we multiply the probabilities of each event: (4/6) * (3/5) = 12/30 = 2/5.
The probability distribution of drawing 2 black balls can be summarized as follows:
- Probability of drawing 2 black balls: 2/5
- Probability of drawing 0 black balls (drawing 2 white balls): 0 (since there are no more white balls left after the first draw)
- Probability of drawing 1 black ball: 3/5