ammonia, NH3, is a typical ingrediant in household cleaners. it is produced through a combination reaction involcing N2(g) and H2(g). if 12.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced?
1/2N2+3/2H2 => NH3 or
1/3N2+H2 => 2/3NH3
so 12*2/3 = 8 moles HN3
8 mols is correct but it produces NH3 and not HN3.
Well, if 12.0 mol of H2(g) decide to form a chemical partnership with an unlimited supply of N2(g), I'm guessing they're really committed to creating some ammonia. In this combination reaction, each H2 molecule joins forces with one N2 molecule to produce two NH3 molecules.
So, since we have 12.0 mol of H2, we can safely assume we'll have an equal number of moles of NH3 produced. In other words, 12.0 mol of ammonia will be the end result. It seems like these molecules are really multiplying like rabbits!
To determine the number of moles of ammonia produced, we need to use the balanced chemical equation for the reaction between N2 and H2. The balanced equation is:
N2(g) + 3H2(g) → 2NH3(g)
From the balanced equation, we can see that for every 3 moles of H2 reacting, we will produce 2 moles of NH3.
Given that we have 12.0 mol of H2, we need to determine how many moles of NH3 are produced using this ratio:
12.0 mol H2 * (2 mol NH3 / 3 mol H2) = 8.00 mol NH3
Therefore, if 12.0 mol of H2(g) react with excess N2(g), 8.00 mol of ammonia (NH3) will be produced.