Physics 11th

a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform ation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

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  1. v=u+at

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  2. Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1)

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  3. Distance covered in 4 secods after tha 5th seconds= S9- s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n-1) The modern sr. sec. Bagpur palwal phone no. 8059892363

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  4. Use v=u+at and form two equations one for acc. And one for . Then on solving u will get d ans. I hope dat helps.. 😀 ☺

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  5. 5s

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  6. Yesss

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