If the nth term of a sequence is 3 x 2^n-1, Write down the first three terms.
3 6 12
what was confusing about this?
To find the first three terms of the sequence, we can substitute the values of n into the formula 3 x 2^(n-1).
Let's start with n = 1:
First term (n = 1): 3 x 2^(1-1) = 3 x 2^0 = 3 x 1 = 3
Now, let's move on to n = 2:
Second term (n = 2): 3 x 2^(2-1) = 3 x 2^1 = 3 x 2 = 6
Finally, let's find the third term by substituting n = 3:
Third term (n = 3): 3 x 2^(3-1) = 3 x 2^2 = 3 x 4 = 12
Therefore, the first three terms of the sequence are: 3, 6, 12.
To find the first three terms of the sequence, we can substitute the values of n into the formula.
Given that the nth term formula is 3 x 2^(n-1), we can find the first term by substituting n = 1 into the formula:
First term (n = 1): 3 x 2^(1-1) = 3 x 2^0 = 3 x 1 = 3
Therefore, the first term of the sequence is 3.
Similarly, we can find the second term by substituting n = 2 into the formula:
Second term (n = 2): 3 x 2^(2-1) = 3 x 2^1 = 3 x 2 = 6
Hence, the second term of the sequence is 6.
Finally, we can find the third term by substituting n = 3 into the formula:
Third term (n = 3): 3 x 2^(3-1) = 3 x 2^2 = 3 x 4 = 12
Thus, the third term of the sequence is 12.
Therefore, the first three terms of the sequence are 3, 6, and 12, respectively.