A precipitate is formed by adding 20.0 ml of 0.200M of sodium phosphate to 30.0 ml of 0.50M Copper sulfate. Please write the ionic equation
Sodium phosphate and copper sulfate are both soluble, whilst copper phosphate is not.
So, copper ions meet phosphate ions and precipate. That is the reaction.
To write the ionic equation for the reaction between sodium phosphate (Na3PO4) and copper sulfate (CuSO4), you need to first identify the ions present in the reactants and products.
The chemical formula for sodium phosphate is Na3PO4, consisting of three sodium ions (Na+) and one phosphate ion (PO4^3-). The chemical formula for copper sulfate is CuSO4, composed of one copper ion (Cu2+) and one sulfate ion (SO4^2-).
In the reaction, sodium phosphate reacts with copper sulfate to form copper phosphate as a precipitate. The balanced equation for this reaction is:
3 Na3PO4 + 2 CuSO4 -> Cu3(PO4)2 + 3 Na2SO4
Now, to write the ionic equation, you need to break down the reactants and products into their respective ions.
The reactants (in their ionic form) are:
3 Na+ + PO4^3- + 2 Cu2+ + SO4^2-
The product (in its ionic form) is:
Cu3(PO4)2
Now, you can write the ionic equation by eliminating any spectator ions that do not participate in the reaction. In this case, the sodium and sulfate ions are spectator ions because they remain unchanged throughout the reaction. Therefore, they can be eliminated from both sides of the equation.
The ionic equation for the reaction is:
3 Na+ + PO4^3- + 2 Cu2+ -> Cu3(PO4)2