The probability of a randomly selected car crashing during a year in a certain country is .0479. If a family has three cars, find the probability that at least one of them has a car crash during a year.
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"At least one" = either 1, 2 or 3.
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
for 1: .0479 * (1-.0479)^2 = ?
for 2: .0479^2 * (1-.0479) = ?
for 3: .0479^3 = ?
Either-or probabilities are found by adding the individual probabilities.posted by PsyDAG