Find an equation for the tangent line of the function f(x)=6+10xe^x at the point (0,6).
f ' (x) = 10x(e^x) + 10e^x
f ' (0) = 0 + 10e^0 = 10
(0,6) is the y-intercept and the slope is 10 , so simply
y = 10x + 6
f ' (0) = 0 + 10e^0 = 10
(0,6) is the y-intercept and the slope is 10 , so simply
y = 10x + 6