please do this with the steps so I can understand this
If 6/square root x^2+4(square root end)=2, then x^2=?
6/√(x^2 + 4) = 2
square both sides
36/(x^2 + 4) = 4
4x^2 + 16 = 36
4x^2 = 20
x^2 = 5
in the following lines l and m are parallel, line t is a transversal. find the missing angles angle x, angle y
/ indicates a line that passes through m and l named t
m--------y/120--------
l---------60/x--------
To solve the equation (6/square root(x^2 + 4 * square root(end))) = 2 and find the value of x^2, we need to follow these steps:
Step 1: Isolate the square root term
Multiply both sides of the equation by square root(x^2 + 4 * square root(end)) to eliminate the fraction:
(6/square root(x^2 + 4 * square root(end))) * square root(x^2 + 4 * square root(end)) = 2 * square root(x^2 + 4 * square root(end))
Simplifying the left side:
6 = 2 * square root(x^2 + 4 * square root(end))
Step 2: Isolate the square root term
Divide both sides of the equation by 2 to isolate the square root term:
6/2 = (2 * square root(x^2 + 4 * square root(end))) / 2
Simplifying:
3 = square root(x^2 + 4 * square root(end))
Step 3: Square both sides of the equation
Raise both sides of the equation to the power of 2:
(3)^2 = (square root(x^2 + 4 * square root(end)))^2
Simplifying:
9 = x^2 + 4 * square root(end)
Step 4: Remove the square root term
Subtract 4 * square root(end) from both sides of the equation:
9 - 4 * square root(end) = x^2
Therefore, x^2 is equal to 9 - 4 * square root(end).