Sea water contains an average of 1.08 x 10^3 ppm of Na+ ion. Calculate the molar concentration of Na+ given that the average density of sea water is 1.02 g/ml.
Well, since you asked for it, here's my attempt at answering your question with a touch of humor!
If sea water were a person, it would definitely need to go on a low-sodium diet because it contains so much Na+! Let's dive into the calculations and find out the molar concentration.
First, we need to convert parts per million (ppm) to grams per liter (g/L). To do this, we multiply the ppm value by the density of sea water. In this case, the density is 1.02 g/mL, so let's do some math!
1.08 x 10^3 ppm * 1.02 g/mL = 1.1016 g/L
Now we can convert grams to moles. The molar mass of sodium (Na) is approximately 22.99 g/mol. So, let's divide the grams of Na+ by the molar mass to get the molar concentration.
1.1016 g/L / 22.99 g/mol ≈ 0.0480 mol/L
So, the molar concentration of Na+ in sea water is approximately 0.0480 mol/L. That's one salty solution, if you ask me!
I hope I was able to make you smile while providing you with the answer. If you have any more questions or need further assistance, feel free to ask!
To calculate the molar concentration of Na+ in sea water, we first need to convert the parts per million (ppm) value to moles.
Given:
Na+ ion concentration in sea water = 1.08 x 10^3 ppm
Density of sea water = 1.02 g/ml
First, we need to determine the mass of Na+ ions present in 1 L of sea water. Since the density of sea water is 1.02 g/ml, the mass of 1 L (1000 ml) of sea water is:
Mass of 1 L of sea water = 1000 ml x 1.02 g/ml = 1020 g
Next, we can calculate the mass of Na+ ions in 1 L of sea water using the ppm value. The ppm value represents the number of parts per million, which can be calculated as follows:
1 ppm = 1 part per million = 1 gram per million grams
Mass of Na+ ions in 1 L of sea water = (1.08 x 10^3 ppm / 1 x 10^6 ppm) x 1020 g = 1.10256 g
Now, to calculate the molar concentration of Na+ ions, we need to convert the mass of Na+ ions (in grams) to moles. The molar mass of Na+ is approximately 22.99 g/mol (rounded to two decimal places).
Number of moles of Na+ ions = Mass of Na+ ions / Molar mass of Na+
Number of moles of Na+ ions = 1.10256 g / 22.99 g/mol = 0.0479 mol (rounded to four decimal places)
Finally, to calculate the molar concentration of Na+ ions, we divide the number of moles by the volume of solution in liters:
Molar concentration of Na+ ions = Number of moles of Na+ ions / Volume of solution (in liters)
Molar concentration of Na+ ions = 0.0479 mol / 1 L = 0.0479 M (rounded to four decimal places)
Therefore, the molar concentration of Na+ ions in sea water is approximately 0.0479 M.
To calculate the molar concentration of Na+ in sea water, we need to convert the given parts per million (ppm) measurement into molarity (M).
Given:
- Average concentration of Na+ ion in sea water = 1.08 x 10^3 ppm
- Average density of sea water = 1.02 g/ml
Step 1: Convert ppm to Molarity (Molar concentration):
To convert ppm to Molarity, we first need to determine the mass of Na+ in 1 liter (1000 ml) of sea water.
1. Determine the mass of Na+:
The mass of Na+ can be calculated using the concentration (ppm) and the density of sea water.
Mass of Na+ = (Concentration x Volume) / 10^6
Given:
Concentration of Na+ = 1.08 x 10^3 ppm
Volume of sea water = 1000 ml
Mass of Na+ = (1.08 x 10^3 x 1000) / 10^6 = 1.08 g
2. Convert gram to moles:
To convert grams to moles, we need to know the molar mass of Na+.
Molar mass of Na+ = 22.99 g/mol
Number of moles of Na+ = Mass of Na+ / Molar mass of Na+
= 1.08 g / 22.99 g/mol
≈ 0.047 mol
Step 2: Calculate the molar concentration:
Molar concentration (Molarity) is calculated by dividing the number of moles by the volume in liters.
Given:
Volume of sea water = 1 liter
Molar concentration of Na+ = Number of moles / Volume
= 0.047 mol / 1 L
= 0.047 M
Therefore, the molar concentration of Na+ in sea water is approximately 0.047 M.
ppm is mg/L so 1.08e3ppm is 1.083e3mg/L. you can convert this to mole/L by simply converting the mg to grams then to mole using m/Mr where m is the mass in grams and Mr is the molar mass of Na (periodic table).
once you get that, you will end up with a mol/L. Then you need to work out the volume of water using its density. Then with that volume, you determine how much Na will be present in that volume of water. this is possible because, you know how much Na in mole are there in one Liter of the solvent from the molarity you first calculated.