Consider the following (Give your answer correct to four decimal places.)

(c) Find P(z > 0.23).
1-0.5910 = .409

(d) Find P(z < 1.51).
1-0.9354=.0655

Four decimal places for 0.409 should be 0.4090.

The second one is correct.

Sorry, the second one is

P(z<1.51), which makes 0.9354 the correct answer.

I tried these answers and it says they are wrong and I do not understand why. I put 0.4090 and 0.9354. Any suggestions as how they might be wrong????

To find P(z > 0.23), you need to look up the corresponding cumulative probability for 0.23 in the standard normal distribution table. The cumulative probability represents the probability of getting a value less than or equal to the given value.

Looking up 0.23 in the standard normal distribution table, you would find that the cumulative probability is approximately 0.5910. However, we want to find the probability of getting a value greater than 0.23, so we subtract this cumulative probability from 1:

P(z > 0.23) = 1 - 0.5910 = 0.409

Therefore, P(z > 0.23) is approximately 0.409.

To find P(z < 1.51), you again need to look up the corresponding cumulative probability for 1.51 in the standard normal distribution table. This time, the cumulative probability represents the probability of getting a value less than the given value.

Looking up 1.51 in the standard normal distribution table, you would find that the cumulative probability is approximately 0.9354. However, we want to find the probability of getting a value less than 1.51, so no adjustment needs to be made.

P(z < 1.51) = 0.9354

Therefore, P(z < 1.51) is approximately 0.9354.