write an equation in general form for the line that passes through A(3,-4) and B(11, 8)
First find the slope m=(y2-y1)/(x2-x1)
you can simply plug in your points A(x1, y1)and B(x2, y2) in to the formula
m=(8-(-4))/(11-3)
Then use point-slope form to get an equation for the line
(y - y1) = m (x - x1) You can use either point A or B for this formula
meaning you can use y1=-4 and x1=3 OR you can use y1=8 and x1=11. It is your choice.
After you'll plug m, x1 and y1 into the formula all you need to do is to simplify it and leave it in the form y= every_other_term_is_on_this_side
is the answer 3x -2y -17= 0?
please get back asap
To find the equation of a line in general form, you need to determine the slope and the y-intercept.
The slope of a line passing through two points (x1, y1) and (x2, y2) can be calculated using the formula: m = (y2 - y1) / (x2 - x1). Let's substitute the values into the formula:
m = (8 - (-4)) / (11 - 3)
m = 12 / 8
m = 3/2
So, we have found the slope m = 3/2.
To find the y-intercept (b), we can substitute one of the given points (A or B) into the equation y = mx + b and solve for b. Let's use point A(3, -4):
-4 = (3/2)(3) + b
-4 = 9/2 + b
To isolate b, let's subtract 9/2 from both sides:
-4 - 9/2 = b
-8/2 - 9/2 = b
-17/2 = b
So, we have found the y-intercept b = -17/2.
Now, we can write the equation of the line in general form using the values we found:
y = (3/2)x - 17/2
Therefore, the equation of the line in general form that passes through points A(3,-4) and B(11, 8) is 2y = 3x - 17.