on turning a corner a motorcyclist rushing at 44 meter per second. find a child on the road 100m away. he applies the brake so as to stop motorcycle within 1m of the child. calculate the time required to stop?

Physics

2.2 To calculate the time required to stop the motorcycle, we can use the following formula:

v^2 = u^2 + 2as

Where:
v = final velocity (0 m/s)
u = initial velocity (44 m/s)
a = acceleration
s = distance

In this case, the initial velocity is 44 m/s, the final velocity is 0 m/s, and the distance is 100 m. We need to find the acceleration of the motorcycle to determine the time it takes to stop.

Rearranging the equation, we have:

a = (v^2 - u^2)/(2s)

Plugging in the values, we can calculate the acceleration:

a = (0^2 - 44^2)/(2 * 100)
a = (-44^2)/200
a = -44^2/200
a = -44 * 44 / 200
a = -968 / 200
a = -4.84 m/s^2

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity. Once we have the acceleration, we can calculate the time using the following formula:

t = (v - u) / a

Plugging in the values, we get:

t = (0 - 44) / -4.84
t = -44 / -4.84
t = 9.09 seconds (rounded to two decimal places)

Therefore, it would take approximately 9.09 seconds to stop the motorcycle.