53. What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)? (1 point)

(x – 2)2 + (y – (–5))2 = 25
(x – (–2))2 + (y – 10)2 = 241
(x – 2)2 + (y – (–5))2 = 241
(x – (–2))2 + (y – 10)2 = 25

The radius is the distance between the centre and the given point, which is

r=sqrt(15^2+4^2)=sqrt(241)
The circle with centre (2,-5) is
(x-2)^2+(y-(-5))^2=r^2
There is only one choice that fits these criteria.