One step of the Ostwald process for manufacturing nitric acid involves making nitrogen monoxide by oxidizing ammonia in the presence of a platinum catalyst: 4NH3 (g) + 502 (g)>> 4NO (g) + 6H2O (g). If the percentage yield is 80.3%, how many grams of NO can be produced from 4.00 times 10^3 grams of NH3?

Question

One step of the Ostwald process for manufacturing nitric acid involves making nitrogen monoxide by oxidizing ammonia in the presence of a platinum catalyst: 4NH3 (g) + 502 (g)>> 4NO (g) + 6H2O (g). If the percentage yield is 80.3%, how many grams of NO can be produced from 4.00 times 10^3 grams of NH3?

Answer 1

try this;

% yield = (exp. yield)/(theoretical yield) x100%

where exp. yield is the experimental yield (what you actually get)

theoretical yield is calculated from the equation using the mass of NH3 to determine the mass of NO.

hope that helps

Answer 2

To find out the number of grams of NO that can be produced, we need to follow these steps:

Step 1: Identify the balanced equation for the reaction.
The balanced equation for the reaction is: 4NH3 (g) + 5O2 (g) >> 4NO (g) + 6H2O (g)

Step 2: Calculate the molar mass of NH3 and NO.
The molar mass of NH3 (Ammonia) is 17.03 g/mol.
The molar mass of NO (Nitric oxide) is 30.01 g/mol.

Step 3: Convert the mass of NH3 to moles of NH3.
Given:
Mass of NH3 = 4.00 x 10^3 grams
Molar mass of NH3 = 17.03 g/mol

Using the formula:
Number of moles = Mass / Molar mass

Number of moles of NH3 = (4.00 x 10^3 g) / (17.03 g/mol)

Step 4: Determine the theoretical yield of NO.
The theoretical yield is the maximum amount of NO that can be produced based on the stoichiometry of the reaction. In this case, it is the number of moles of NH3 multiplied by the stoichiometric ratio between NH3 and NO.

From the balanced equation:
4 moles NH3 produces 4 moles NO

So, the number of moles of NO = Number of moles of NH3.

Step 5: Calculate the actual yield of NO.
Given that the percentage yield is 80.3%, we can find the actual yield using the formula:

Actual yield = Percentage yield / 100 * Theoretical yield

Actual yield of NO = (80.3 / 100) * (Number of moles of NO)

Step 6: Convert moles of NO to grams of NO.
Given:
Molar mass of NO = 30.01 g/mol
Number of moles of NO = Actual yield of NO (from Step 5)

Using the formula:
Mass = Number of moles * Molar mass

Mass of NO = Number of moles of NO * Molar mass of NO

Now, you can substitute the values into the equation and solve for the mass of NO.