Factorise (x - 1)^2 - 4y^2

(X-1)(x-1)-4y^2

x^ 2 -x -x +1 -4y^2

x^2 -2x + 1 -4y^2

(x -2y-1)(x +2y -1)

or, as the difference of squares,

((x-1)-2y)((x-1)+2y)

Thanks guys:)

To factorize the given expression (x - 1)^2 - 4y^2, we can use the difference of squares formula, which states that a^2 - b^2 = (a + b)(a - b).

Let's apply this formula to the given expression:

(x - 1)^2 - 4y^2 = [(x - 1) + 2y][(x - 1) - 2y]

Therefore, the factored form of (x - 1)^2 - 4y^2 is [(x - 1) + 2y][(x - 1) - 2y].

To solve this type of expression, it's important to recognize the pattern of a difference of squares and apply the difference of squares formula to factorize it.