If RS=8y+4, ST=4y+8, and RT=36, find the value of y.
RS=3X+1,ST=2x-2,And RT=64 Find The Vaule Of X ?
To find the value of y, we can use the given information about the lengths of the line segments RS, ST, and RT.
We know that RS + ST = RT (by the segment addition postulate). So, we can write the equation:
(8y + 4) + (4y + 8) = 36
Simplifying the equation, we get:
8y + 4 + 4y + 8 = 36
12y + 12 = 36
Next, we can subtract 12 from both sides of the equation:
12y + 12 - 12 = 36 - 12
12y = 24
Finally, divide both sides of the equation by 12 to solve for y:
12y / 12 = 24 / 12
y = 2
Therefore, the value of y is 2.