Devon purchased tickets to an air show for 9 adults and 2 children. The
total cost was $252. The cost of a child's ticket was $6 less than the cost of an adult's ticket. Find the price of an adult's ticket and a child's ticket.
9A + 2C = 252
C = A -6
9A + 2( A -6) = 252
9A + 2A - 12 = 252
11A = 264
11A/11 = 254/11
A = 24
C = 18
Typo
11A/11 = 264/11
To solve this problem, we can create an equation based on the given information.
Let's assume the price of an adult's ticket is x dollars.
According to the problem, the price of a child's ticket is $6 less than the cost of an adult's ticket. So, the price of a child's ticket would be (x - $6).
Now, let's calculate the total cost of the tickets:
For 9 adults, the total cost would be 9x dollars.
For 2 children, the total cost would be 2(x - $6) dollars.
According to the problem, the total cost of all the tickets was $252. Therefore, we can write the equation:
9x + 2(x - $6) = $252
Now, let's solve the equation to find the price of an adult's ticket (x) and the price of a child's ticket (x - $6).
Simplifying the equation:
9x + 2x - $12 = $252
11x - $12 = $252
Adding $12 to both sides of the equation:
11x = $252 + $12
11x = $264
Dividing both sides of the equation by 11:
x = $264 / 11
x = $24
Thus, the price of an adult's ticket is $24.
Now, let's find the price of a child's ticket (x - $6):
Child's ticket price = $24 - $6 = $18
Therefore, the price of an adult's ticket is $24, and the price of a child's ticket is $18.