# Chemistry

Consider the reaction:

2CO(g) + O2(g) equilibrium 2CO2 (g)

Write the equilibrium expression for this reaction.

Keq = ??

Addition of a catalyst to this reaction would have what effect on the equilbrium?

Addition of a catalyst to this reaction would have what effect on the rate?

1. catalyst does not change the equilibrium, only the speed of the reaction.

Keq=[CO2]^2 /([CO]^2*[O2])

posted by bobpursley
2. i wait to slove it 2CO+O2 in reversible constant Value is 1.250

posted by Hariom verma

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