What is the approximate ratio in conductivity of silicon doped with 37 ppm to silicon doped with 5 ppm
37 ppm/ 5ppm
ya its 7.4. got right.
To determine the approximate ratio in conductivity between silicon doped with 37 ppm (parts per million) and silicon doped with 5 ppm, we need to understand the relationship between doping concentration and conductivity in silicon.
Doping refers to the intentional introduction of impurities into a semiconductor material, such as silicon, to change its electrical properties. The most common dopants used for silicon are boron (B), phosphorus (P), and arsenic (As).
In general, when silicon is doped with a higher concentration of impurities, the conductivity increases. This is because these impurities introduce extra electrons (n-type doping) or holes (p-type doping) into the silicon lattice, which can participate in the conduction of electrical charge.
However, without specific information about the type (n-type or p-type) of dopant and the doping profile used in the silicon samples, we cannot accurately determine the conductivity ratio based solely on the doping concentration.
To obtain the precise ratio in conductivity, we would need to consider additional factors such as the dopant type, the doping method (e.g., diffusion or ion implantation), the temperature, and the concentration and mobility of the majority carriers (electrons or holes) in the doped silicon.
Therefore, without more details, we can only make a general statement that silicon doped with 37 ppm is likely to have higher conductivity compared to silicon doped with 5 ppm. However, the exact magnitude of the conductivity ratio cannot be determined without additional information.