statistics
suppse you received a shipment of nine televisions. four of the television are defective. If two televisions are random;y selected compute the probability at least on of the two televisions does not work

Let
D=event that a television selected is defective
and
~D=event that a television selected is NOT defective
Then probability that both are not defective:
P(~D~D)=(5/9)(4/8)=5/18
Therefore at least one defective is its complement
P( (~D~D)') = 15/18 = 13/18
posted by MathMate

Suppose you just received a shipment of tenten televisions. TwoTwo of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?
posted by Anonymous
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