# statistics

suppse you received a shipment of nine televisions. four of the television are defective. If two televisions are random;y selected compute the probability at least on of the two televisions does not work

1. Let
D=event that a television selected is defective
and
~D=event that a television selected is NOT defective

Then probability that both are not defective:
P(~D~D)=(5/9)(4/8)=5/18

Therefore at least one defective is its complement
P( (~D~D)') = 1-5/18 = 13/18

posted by MathMate
2. Suppose you just received a shipment of tenten televisions. TwoTwo of the televisions are defective. If two televisions are randomly​ selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not​ work?

posted by Anonymous

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