Find the area under the standard normal curve between -1.32 and the mean, P(-1.32 < z < 0.00). (Give your answer correct to four decimal places.)

0.0968

Your answer corresponds to P(-0.25<z<0).

Look up a probability table (or use your calculator) for +1.32.
Many normal probability tables are one-tail from -∞ so you need to subtract 0.5 from the result, taking advantage of symmetry of the normal distribution.

Need answer.

To find the area under the standard normal curve, between -1.32 and the mean, P(-1.32 < z < 0.00), you can use a standard normal distribution table.

The given value, -1.32, represents the z-score. It represents the number of standard deviations below the mean.

To find the area under the curve, you need to find the probability corresponding to the z-scores -1.32 and 0.00.

From the standard normal distribution table, the cumulative probability for z = -1.32 is 0.0968.

Therefore, the area under the standard normal curve between -1.32 and the mean, P(-1.32 < z < 0.00), is 0.0968, or 9.68% (rounded to four decimal places).

To find the area under the standard normal curve between -1.32 and the mean, P(-1.32 < z < 0.00), you can use a standard normal distribution table or a graphing calculator with a normal distribution function.

If you're using a standard normal distribution table, you need to find the z-scores associated with -1.32 and 0.00. The z-score is a measure of how many standard deviations an observation is away from the mean.

Using the table, you can find that the z-score for -1.32 is approximately -0.9051 and the z-score for 0.00 is 0.5000.

The area under the standard normal curve between -1.32 and 0.00 is equal to the difference in the cumulative probability between these two z-scores.

P(-1.32 < z < 0.00) = P(z < 0.00) - P(z < -1.32)

From the standard normal distribution table, you can find that P(z < 0.00) is approximately 0.5000 and P(z < -1.32) is approximately 0.0968.

Therefore, the area under the standard normal curve between -1.32 and the mean is approximately:

P(-1.32 < z < 0.00) = 0.5000 - 0.0968 = 0.4032

So, the answer to the question, rounded to four decimal places, is 0.4032.