Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds then together they would weigh 250 pounds. How much does each of them weigh? let x be ken's weight.
thanks
Joe weighs 30lbs less than 2wice kens weight
J=2x-30
ken gains 10lbs, then 2gether would weigh 250
(x+10)+J = 250
J=joe's weight.
solve them simultaneously..
hope that helps
im confused can you explain a little more cause i need a full equation and im really confused
you need to construct simultaneous equations from the information;
first equation is from; Joe weighs 30lbs less than 2wice kens weight. and x is ken's weight. so twice kens weight is 2x. 30lbs less than twice kens weight is 2x-30. these equals to Joes weight
J=2x-30 (1)
we cannot work with this equation alone because, there are two unknowns J and x. so we need another equation which is obtained from; If ken gains 10 pounds then together they would weigh 250 pounds.
i.e. if ken gains 10lbs (x+10), then together (with J) will equal to 250.
(x+10)+J = 250 (2)
Now we can solve for each weight either by substitution or elimination method..
To solve this problem, let's first set up the equations based on the given information.
We know that Joe weighs 30 pounds less than twice Ken's weight. So, Joe's weight can be represented as 2x - 30, where x represents Ken's weight.
If Ken gains 10 pounds, his new weight will be x + 10.
Together, their total weight will be 250 pounds. So we have the equation:
(2x - 30) + (x + 10) = 250
Now, let's solve for x.
Combining like terms, we can simplify the equation to:
3x - 20 = 250
Adding 20 to both sides of the equation:
3x = 270
Divide both sides by 3:
x = 90
Therefore, Ken weighs 90 pounds.
Now, we can find Joe's weight by substituting x with 90 in the equation 2x - 30:
Joe's weight = 2(90) - 30 = 180 - 30 = 150 pounds.
Therefore, Joe weighs 150 pounds.
To summarize:
Ken weighs 90 pounds, and Joe weighs 150 pounds.