A parallel RL circuit has a reactance of 250 W and a resistance of 125 W. The phase angle of the circuit impedance is
tanφ=X(L)/R = 250/125 = 2
φ=tan⁻¹2=63.4⁰
thanks Elena ive got the same answer. i hate it when the applied answer isn't listed
18.4°
-18.4°
26.6°
-26.6°
*None of the above
To find the phase angle of a parallel RL circuit, we need to calculate the impedance of the circuit first.
The impedance of a parallel RL circuit is given by the formula:
Z = sqrt(R^2 + (Xl - Xc)^2)
Where:
Z is the impedance,
R is the resistance,
Xl is the inductive reactance, and
Xc is the capacitive reactance.
In this case, we are given the values of R (resistance) and Xl (inductive reactance). However, to find the phase angle, we need the value of Xc (capacitive reactance).
The capacitive reactance (Xc) can be calculated using the formula:
Xc = 1 / (2πfC)
Where:
Xc is the capacitive reactance,
f is the frequency of the circuit, and
C is the capacitance.
Since we don't have the values of frequency or capacitance, it is not possible to calculate the phase angle with the given information.