Strychnine, C21H22N2O2(aq) is a weak base but a powerful poison. Calculate the pH of a 0.001 mol/L solution of strychnine. The Kb of strychnine is 1.0 x 10^-6
My work:
I called Strychnine SN
SN + HOH --> SNH+ + OH-
Kb = (SNH+)(OH-)/(SN)
(SNH+) = x
(OH-) =x
(SN) = 0.001-x
Plugging into Kb
Kb = (x)(x)/(0.001-x)
Can someone please solve for x = (OH-)?
Thank you