Suppose a box of marbles contains equal numbers of red marbles and yellow marbles but twice as many green marbles as red marbles. Draw one marble from the box and observe its color. Assign probabilities to the elements in the sample space. (Give your answers as fractions.)

Question

Suppose a box of marbles contains equal numbers of red marbles and yellow marbles but twice as many green marbles as red marbles. Draw one marble from the box and observe its color. Assign probabilities to the elements in the sample space. (Give your answers as fractions.)

Red Incorrect: Your answer is incorrect. .
Green Incorrect: Your answer is incorrect. .
Yellow

Answer 1

Nora 4:

Hint for you.
If you provide attempted answers to the question, do add "(answer check)" to the end of "school subject", especially if you have a whole series of questions which makes it look it homework dumping.

Answer 2

Thank you, one told me not to post unless I had an answer and sometimes I don't and that is why I post it and say don't use these numbers just do an example for me to look at.

Answer 3

To assign probabilities to the elements in the sample space, we first need to determine the total number of marbles in the box.

We know that the box contains an equal number of red and yellow marbles. Let's say that number is x.

We also know that there are twice as many green marbles as there are red marbles. So the number of green marbles would be 2x.

Therefore, the total number of marbles in the box would be x + x + 2x = 4x.

Now, let's assign probabilities to each element in the sample space.

- The probability of drawing a red marble would be the number of red marbles (x) divided by the total number of marbles (4x). So the probability of drawing a red marble is x/4x, which simplifies to 1/4.

- The probability of drawing a green marble would be the number of green marbles (2x) divided by the total number of marbles (4x). So the probability of drawing a green marble is 2x/4x, which simplifies to 1/2.

- The probability of drawing a yellow marble would be the number of yellow marbles (x) divided by the total number of marbles (4x). So the probability of drawing a yellow marble is x/4x, which simplifies to 1/4.

Therefore, the probabilities for each element in the sample space are:
- Red: 1/4
- Green: 1/2
- Yellow: 1/4

Answer 4

I got 1/3 for red

I got 2/3 for yellow
and 1/3 for green but they was wrong, Since you only have three colors I put that on the bottom and went by equal numbers on top. Can someone explain this to me.

Answer 5

Hints:

Work out the following:

- equal numbers of red marbles and yellow marbles (call
x=number of red
x=number of yellow

- twice as many green marbles as red marbles
2x=number of green

Now work out the sample space and the corresponding probabilities.

Suppose a box of marbles contains equal numbers of red marbles and yellow marbles but twice as many green marbles as red marbles. Draw one marble from the box and observe its color. Assign probabilities to the elements in the sample space. (Give your answers as fractions.)

Nora 4:

Thank you, one told me not to post unless I had an answer and sometimes I don't and that is why I post it and say don't use these numbers just do an example for me to look at.

89o7uo0p

To assign probabilities to the elements in the sample space, we first need to determine the total number of marbles in the box.

I got 1/3 for red

Hints: