A single die is rolled.
(a) What is the probability that the number on top is a 3. (Give your answer correct to two decimal places.)
(b) What is the probability that the number on top is an odd number. (Give your answer correct to two decimal places.)
(c) What is the probability that the number on top is a number less than 5. (Give your answer correct to two decimal places.)
(d) What is the probability that the number on top is a number no greater than 3. (Give your answer correct to two decimal places.)
2/3
4/5
a) The probability of rolling a 3 on a single die is about as likely as finding a parking spot right in front of the gym on January 1st. It's a rare occasion, happening only once in every 6 tries. So the probability of rolling a 3 is 1/6, which is approximately 0.17 when rounded to two decimal places.
b) If odd numbers were pets, they would definitely be the cats of the dice world. Unpredictable, a bit mysterious, and always causing curiosity. Out of the six possible outcomes, three are odd numbers - 1, 3, and 5. So the probability of rolling an odd number is 3/6, which simplifies to 1/2, approximately 0.50.
c) Consider numbers less than 5 as treasure hunts, and the die as the map. Out of the six possible numbers that could present themselves, four are less than 5 - 1, 2, 3, and 4. So the probability of rolling a number less than 5 is 4/6, which simplifies to 2/3, approximately 0.67.
d) Now let's focus on the numbers no greater than 3, like trying to fit into your favorite pair of pants after indulging in holiday feasts. Out of the six possible outcomes, three are equal to or less than 3 - 1, 2, and 3. So the probability of rolling a number no greater than 3 is 3/6, which simplifies to 1/2, approximately 0.50.
To answer these questions, we need to understand the concept of probability.
Probability is the likelihood of an event occurring, expressed as a fraction or decimal between 0 and 1. In this case, we are rolling a single die, so there are six possible outcomes: 1, 2, 3, 4, 5, and 6.
(a) To find the probability that the number on top is a 3, we need to determine how many favorable outcomes there are (a 3) out of the total number of possible outcomes (6). Since there is only one face of the die with a 3, the probability is 1/6, which is approximately 0.17 when rounded to two decimal places.
(b) To find the probability that the number on top is an odd number, we need to determine how many favorable outcomes there are (the odd numbers 1, 3, and 5) out of the total number of possible outcomes (6). Since there are three odd numbers, the probability is 3/6, which simplifies to 1/2 or 0.50.
(c) To find the probability that the number on top is a number less than 5, we need to determine how many favorable outcomes there are (the numbers 1, 2, 3, and 4) out of the total number of possible outcomes (6). Since there are four numbers less than 5, the probability is 4/6, which simplifies to 2/3 or approximately 0.67 when rounded to two decimal places.
(d) To find the probability that the number on top is a number no greater than 3, we need to determine how many favorable outcomes there are (the numbers 1, 2, and 3) out of the total number of possible outcomes (6). Since there are three numbers no greater than 3, the probability is 3/6, which simplifies to 1/2 or 0.50.
a. probability=numberwaysright/total number ways=1/6
b. there are the following odd numbers: 1,3,5. There are six possible numbers
probability=3/6=1/2
c. Less than five means not 5, or 6
probability=1-2/6
d. no greater than three means 1,2, or 3
probability=3ways/6possible=1/2
a. 1/6 +1/6 = 2/6 or 1/3 = .33
b. 3/6 + 1/6 = 4/6 or 2/3 = .67
c. 4/6 + 2/6 = 6/6 or 1.00
d. 1/6 + 1/6 = 2/6 or 1/3 = .33
Please tell me how I am missing these, and give me right formula, I do not want you to work them out, I need to learn this stuff, just help on formula if I am using the wrong one.