Christy rolls a number cube and then chooses a card from a set numbered 1 through 9. What is the probability that she will roll an even number and choose an odd card?
Would the answer be 2/15?
pr(even, odd)=1/2*5/9
I forgot to mention the die has 6 sides.
To find the probability, we need to determine the number of favorable outcomes, which is the number of ways in which Christy can roll an even number and choose an odd card, and the total number of possible outcomes, which is the total number of choices she can make.
First, let's determine the total number of possible outcomes. The number cube has 6 sides, so there are 6 possible outcomes when rolling it. The set of cards numbered 1 through 9 has a total of 9 cards, so there are 9 possible outcomes when choosing a card.
Since these events are independent (the outcome of rolling the number cube does not affect the choice of the card), we can find the probability by multiplying the probabilities of each event.
The probability of rolling an even number on the number cube is 3/6, as there are three even numbers (2, 4, and 6) out of a total of six possible numbers.
The probability of choosing an odd card from the set numbered 1 through 9 is 5/9 since there are five odd numbers (1, 3, 5, 7, and 9) out of a total of nine numbers.
To find the probability of both events occurring, we multiply these probabilities: (3/6) * (5/9) = 15/54.
To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor (GCD), which is 3: (15/3) / (54/3) = 5/18.
Therefore, the probability that Christy will roll an even number and choose an odd card is 5/18, not 2/15.