Six friends want to buy pizza and need to decide between two deals. The first deal is for two pizzas for $7.00 each for a pizza with a 10 inch diameter. Or a second deal with one pizza with a 14 inch diameter for $15.00. The friends decide to buy the offer with the most pizza for each person. How do I solve for the six of each?

one 14" pizza has 196π in^2

two 10" pizzas have 200π in^2

actually, I used the size for the radius instead of the diameter, but the ratios stay the same.

To solve for the six friends buying each deal, we need to calculate the amount of pizza each deal provides per person.

First, let's determine the area of each pizza. The area of a circle can be calculated using the formula: Area = π * (radius)^2.

For the first deal, the pizza has a diameter of 10 inches, so the radius would be half of that, which is 10/2 = 5 inches.

For the second deal, the pizza has a diameter of 14 inches, so the radius would be half of that, which is 14/2 = 7 inches.

Calculating the area for each pizza:
- First deal: π * (5)^2 = 3.14 * 25 = 78.5 square inches
- Second deal: π * (7)^2 = 3.14 * 49 = 153.86 square inches

Next, let's calculate the amount of pizza per person for each deal.

In the first deal, two pizzas are provided. So, the total amount of pizza available in this deal is 2 * 78.5 = 157 square inches.

In the second deal, there is only one pizza. Therefore, the total amount of pizza available in this deal is 153.86 square inches.

Now, let's calculate the pizza per person for each deal.

For the first deal, the pizza per person is 157 square inches divided by 6 friends = 26.17 square inches per person.

For the second deal, the pizza per person is 153.86 square inches divided by 6 friends = 25.64 square inches per person.

Therefore, the first deal provides more pizza per person than the second deal.

So for the six friends, it would be better to choose the first deal, which offers two pizzas for $7.00 each, with a 10-inch diameter.