The person who helped me before was not very helpful.

ABC has vertices A(3,2,-5), B(4,-1,7) and C(-8,3,-6).

a) Determine the area of ABC.

b) Determine the coordinates of point D such that ABCD is a parallelogram.

c) Is the parallelogram a rectangle? Justify your answer.

Given two vectors u and v, forming two sides of a parallelogram, u+v is the corner opposite (0,0). Here, we can take

u = B-A = (1,-3,12)
v = C-A = (11,1,-1)

The area of ∆ (not ) ABC is half the area of the parallelogram ABCD. So, it is

1/2 |uxv| = 1/2 |(-9,133,34)| = 1/2 √18926 = 68.79

The parallelogram is not a rectangle since

uv = 11-3-12 = -4 ≠ 0

To determine the area of triangle ABC, you can use the formula for the magnitude of the cross product of two vectors. The cross product of two vectors gives a vector that is perpendicular to both of them, and its magnitude represents the area of the parallelogram formed by the vectors.

a) To find the area of ∆ABC, we need to calculate the magnitude of the cross product of two vectors formed by subtracting one point from another.

Let's calculate vector AB and vector AC:

Vector AB = B - A = (4, -1, 7) - (3, 2, -5) = (1, -3, 12)

Vector AC = C - A = (-8, 3, -6) - (3, 2, -5) = (-11, 1, -1)

Now, calculate the cross product of AB and AC:

Cross product = AB × AC = (1, -3, 12) × (-11, 1, -1)

To find the cross product, we can calculate the determinants:

i j k
1 -3 12
-11 1 -1

Using the formula for determinant, we can find the cross product as follows:

i(det) - j(det) + k(det) = i(35) - j(145) + k(14) = (35, -145, 14)

Now, calculate the magnitude of the cross product to find the area of the triangle:

Area of triangle = |Cross product| = √(35^2 + (-145)^2 + 14^2)

Calculate the expression above to find the area of triangle ABC.

b) To find the coordinates of point D such that ABCD forms a parallelogram, we can use the fact that opposite sides of a parallelogram are parallel and congruent.

Since vectors AB and CD are parallel, we can use the properties of vector addition and subtraction to find point D.

Point D can be expressed as:

D = C + (B - A)

Calculate the expression above using the given values of points A, B, and C to find the coordinates of point D.

c) To determine if the parallelogram ABCD is a rectangle, we need to check if its adjacent sides are perpendicular to each other.

Calculate the dot product of vectors AB and BC, and also calculate the dot product of vectors BC and CD. If the dot product of these vectors equals zero for both cases, then the adjacent sides are perpendicular, and the parallelogram is a rectangle.

To find the dot product, multiply the corresponding components of the vectors and sum the results:

Dot product AB · BC = (1, -3, 12) · (BC Coordinates)

Dot product BC · CD = (BC Coordinates) · (-11, 1, -1)

Calculate these dot products using the given values to determine if they are zero. If they are, then the parallelogram ABCD is a rectangle.