A gaseous mixture containing 6 moles of oxygen, 8 moles of helium and 6 moles of carbon dioxide in a container under a pressure of 40 atm. Calculate the partial pressure of th3 individual gases.?
Here is how to do one of them.
XO2 = mols O2/total mols.
Then pO2 = XO2*Ptotal
To calculate the partial pressure of each gas in the mixture, we need to use Dalton's Law of Partial Pressures. According to this law, the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of each gas.
In this case, we have three gases: oxygen (O2), helium (He), and carbon dioxide (CO2). We are given the total pressure of the mixture as 40 atm, and the number of moles of each gas.
To calculate the partial pressure of each gas, we need to find the mole fraction of each gas and then multiply it by the total pressure.
The mole fraction (X) of a gas is given by the ratio of the number of moles of that gas to the total number of moles in the mixture.
1. Calculate the total number of moles in the mixture:
Total moles = moles of oxygen + moles of helium + moles of carbon dioxide
= 6 moles + 8 moles + 6 moles
= 20 moles
2. Calculate the mole fraction of each gas:
Mole fraction of oxygen (Xoxygen) = moles of oxygen / total moles
= 6 moles / 20 moles
= 0.3
Mole fraction of helium (Xhelium) = moles of helium / total moles
= 8 moles / 20 moles
= 0.4
Mole fraction of carbon dioxide (Xcarbon dioxide) = moles of carbon dioxide / total moles
= 6 moles / 20 moles
= 0.3
3. Calculate the partial pressure of each gas:
Partial pressure of oxygen = Xoxygen * total pressure
= 0.3 * 40 atm
= 12 atm
Partial pressure of helium = Xhelium * total pressure
= 0.4 * 40 atm
= 16 atm
Partial pressure of carbon dioxide = Xcarbon dioxide * total pressure
= 0.3 * 40 atm
= 12 atm
Therefore, the partial pressure of oxygen is 12 atm, the partial pressure of helium is 16 atm, and the partial pressure of carbon dioxide is 12 atm.