Consider the following.
P(A) = 0.27 and P(B) = 0.36,
A and B are mutually exclusive events
(a) Find the probability P(A). (Give your answer correct to two decimal places.)
(b) Find the probability P(B). (Give your answer correct to two decimal places.)
(c) Find the probability P(A or B). (Give your answer correct to two decimal places.)
(d) Find the probability P(A and B). (Give your answer correct to two decimal places.)
Hints:
P(A∪B)=P(A)+P(B)+P(A∩B)
So if any three of the four probabilities are known, we can find the fourth one.
Note:
Events A and B are mutually exclusive if and only if P(A∩B)=0.
sorry this has not helped me at all....I am so confused on this stuff...
.68
To solve this problem, we'll use some basic principles of probability.
(a) To find the probability of event A (P(A)), you simply use the given value: P(A) = 0.27.
(b) Similarly, to find the probability of event B (P(B)), you use the given value: P(B) = 0.36.
(c) To find the probability of event A or B (P(A or B)), you add the probabilities of A and B, but subtract the probability of them occurring together since they are mutually exclusive events.
P(A or B) = P(A) + P(B) - P(A and B)
Since A and B are mutually exclusive, P(A and B) is 0. So, P(A or B) = P(A) + P(B) = 0.27 + 0.36 = 0.63.
Therefore, the probability of event A or event B occurring is 0.63.
(d) Since A and B are mutually exclusive, they cannot occur together. So, the probability of A and B occurring simultaneously is 0.
Therefore, the probability of event A and event B occurring is 0.