# Algebra

Hi, can I have some help with my permutation/combination homework?

"Find the number of 5-card hands that contain the cards specified."

1. five red cards
2. five cards, none are number cards
3. five cards of the same suit

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1. 1. there are 13 red cards, you want 5 of those
number of hands with 5 red = C(13,5) = 1287

2. there are 16 non-number cards ,
number of 5 card hands from that is
C(16,5)
= 4368

3. could be 4 different suits, in #1 we did the reds
so in this case it would be 4xC(13,5) = 4(1287) = 5148

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posted by Reiny

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