there are two different problems, one is like this -3+x=5 and 7x+10=59 someone please tell me how to set these up.
-3+x=5
Add 3 to both sides of the equation.
7x+10=59
Subtract 10 from both sides.
7x+10=59
10-7x+10=59-10
3x+10=49
???
-3+x=5
3+(-3)+x=5+3
x=8
Is this right Ms.Sue?
To solve the equations -3+x=5 and 7x+10=59, we need to isolate the variable, x, on one side of the equation. Here's how to set up and solve both problems step by step:
1. -3 + x = 5:
- Start by moving the constant term (-3) to the other side of the equation. To do that, we can add 3 to both sides of the equation.
- This gives us: x = 5 + 3.
- Simplifying further, we have: x = 8.
- So the solution to -3 + x = 5 is x = 8.
2. 7x + 10 = 59:
- Begin by isolating the variable term (7x) on one side of the equation. To do that, we can subtract 10 from both sides.
- This gives us: 7x = 59 - 10.
- Simplifying further, we have: 7x = 49.
- To solve for x, divide both sides of the equation by 7.
- This gives us: x = 49/7.
- Simplifying further, we have: x = 7.
- So the solution to 7x + 10 = 59 is x = 7.
Therefore, the solutions are x = 8 for -3 + x = 5 and x = 7 for 7x + 10 = 59.