How many grams of glucose C6H12O6 would you need to make 250 mL of 1.0M solution?
250 ml of a 1.0 M glucose solution contains 0.25 moles of glucose.
Each mole of glucose has a mass of 180 g.
0.25 x 180 = ___ g
To calculate the mass of glucose needed to make a 1.0M solution in 250 mL of solution, we need to use its molar mass and the formula for molarity.
1. First, determine the molar mass of glucose (C6H12O6). The atomic masses of carbon (C), hydrogen (H), and oxygen (O) are approximately 12.01 g/mol, 1.01 g/mol, and 16.00 g/mol, respectively.
Molar mass of glucose (C6H12O6) = (6 * 12.01 g/mol) + (12 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
≈ 180.18 g/mol
2. Next, use the formula for molarity to calculate the number of moles of glucose required:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Rearranging the formula, we get:
moles of solute = Molarity (M) * volume of solution (in liters)
Since we want a 1.0M solution with a volume of 250 mL (which is equivalent to 0.250 L), we can substitute the values into the equation:
moles of solute = 1.0 M * 0.250 L
= 0.250 moles
3. Finally, calculate the mass of glucose using the moles of solute and the molar mass:
mass of glucose = moles of solute * molar mass of glucose
= 0.250 moles * 180.18 g/mol
≈ 45.04 grams
Therefore, you would need approximately 45.04 grams of glucose (C6H12O6) to make a 250 mL 1.0M solution.
To calculate the number of grams of glucose (C6H12O6) required to make a 1.0M solution in 250 mL, we need to follow a few steps.
Step 1: Understand the formula weight of glucose (C6H12O6)
The formula weight of glucose (C6H12O6) is calculated by adding up the atomic weights of all its constituent elements. The atomic weights are as follows:
C (Carbon) = 12.01 g/mol
H (Hydrogen) = 1.008 g/mol
O (Oxygen) = 16.00 g/mol
Thus, the formula weight of glucose (C6H12O6) can be calculated as:
(6 * 12.01) + (12 * 1.008) + (6 * 16.00) = 180.18 g/mol
Step 2: Calculate the number of moles of glucose required
To make a 1.0M solution, we need one mole of glucose in one liter of solution. Since we have 250 mL (0.25 L) of solution, we need to calculate the number of moles required.
Moles = Molarity (M) * Volume (L)
Moles = 1.0 mol/L * 0.25 L
Moles = 0.25 mol
Step 3: Calculate the mass of glucose required
To calculate the mass of glucose required, we need to use the mole-to-mass conversion.
Mass = Moles * Formula Weight
Mass = 0.25 mol * 180.18 g/mol
Mass = 45.045 g
Therefore, you would need 45.045 grams of glucose (C6H12O6) to make 250 mL of a 1.0M solution.