calculate the molarity of 29.25 grams of NaCl in 2.0 liters of solution
To calculate the molarity, we need to know the formula weight of NaCl, which is the sum of the atomic weights of sodium (Na) and chlorine (Cl).
- The atomic weight of sodium (Na) is 22.99 grams/mole.
- The atomic weight of chlorine (Cl) is 35.45 grams/mole.
Therefore, the formula weight of NaCl is 22.99 + 35.45 = 58.44 grams/mole.
Next, we need to calculate the number of moles of NaCl in the given mass.
- Moles = mass / formula weight
- Moles = 29.25 grams / 58.44 grams/mole ≈ 0.5 moles
Finally, we can calculate the molarity using the formula:
- Molarity = moles of solute / volume of solution in liters
- Molarity = 0.5 moles / 2.0 liters = 0.25 M
So, the molarity of 29.25 grams of NaCl in 2.0 liters of solution is approximately 0.25 M.
To calculate the molarity of a solution, you need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
To solve this problem, we'll follow these steps:
Step 1: Calculate the number of moles of NaCl.
To do this, you need to know the molar mass of NaCl, which is 58.44 g/mol. Divide the given mass of NaCl by its molar mass:
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
Moles of NaCl = 29.25 g / 58.44 g/mol
Moles of NaCl = 0.5 mol
Step 2: Calculate the molarity.
Now, you can use the moles of NaCl and the volume of the solution to calculate the molarity:
Molarity (M) = Moles of NaCl / Volume of solution
Molarity (M) = 0.5 mol / 2.0 L
Molarity (M) ≈ 0.25 M
So, the molarity of the solution containing 29.25 grams of NaCl in 2.0 liters of solution is approximately 0.25 M.
mols NaCl = grams/molar mass, then
M = mols/L