A solution is made by mixing 25.0 mL of toluene C6H5CH3 d=0867gmL with 135.0 mL of benzene C6H6 d=0874gmL . Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are
how would i start this problem?
Start by convert 20.0 mL toluene to mass, then convert that to mols. mols = g/molar mass.
Then convert benzene to mass.
molality toluene = mols toluene/kg benzene.
To solve this problem, you need to calculate the molarity (M) and molality (m) of the toluene solution. Let's start by calculating the molarity.
Molarity (M) is calculated by dividing the moles of solute by the volume of the solution in liters. To determine the moles of toluene, you need to know its mass and molar mass.
The molar mass of toluene (C6H5CH3) can be calculated by adding up the atomic masses of all its constituent elements:
Molar mass of C6H5CH3 = (6 * atomic mass of carbon) + (5 * atomic mass of hydrogen) + (1 * atomic mass of carbon) + (3 * atomic mass of hydrogen)
Next, you need to determine the moles of toluene using its mass (volume * density) and molar mass.
First, let's calculate the mass of toluene:
Mass of toluene = volume * density
= 25.0 mL * 0.867 g/mL
Now, convert the volume to liters:
Volume of toluene = 25.0 mL = 25.0 mL * (1 L / 1000 mL)
The moles of toluene can be calculated using the formula:
moles = mass / molar mass
Now that you have calculated the moles, divide it by the total volume of the solution (in liters) to obtain the molarity:
Molarity (M) = moles / total volume of solution in liters
Repeat the same steps for calculating the molality (m), but instead of dividing by the total solution volume in liters, you will divide by the mass of the solvent (benzene) in kilograms.
Molality (m) = moles / mass of solvent in kg
Once you have the moles of toluene and benzene, and the respective masses, you can substitute the values into the equations and calculate the molarity and molality of the toluene solution.