A person of mass 50kg rides an elevator whose motion consist of
(a)acceleration upward at 3m/s
(b)constant velocity
(c)acceleration downward at 3m/s
Given that g=9.8m-2 down, find the person's weight during each stage of the lift ride?
To find the person's weight during each stage of the elevator ride, we need to consider the different forces acting on the person in each stage.
(a) Acceleration upward at 3 m/s^2:
During this stage, the person experiences an upward force greater than their weight due to the acceleration. We can use the equation F = m * a to find the net force acting on the person. The person's weight can be calculated by multiplying their mass by the acceleration due to gravity (g = 9.8 m/s^2).
The net force acting on the person can be found using the equation:
F_net = m * a
Weight during acceleration upward = m * (g + a)
Substituting the given values:
Weight during acceleration upward = 50 kg * (9.8 m/s^2 + 3 m/s^2)
(b) Constant velocity:
When the elevator is moving at a constant velocity, the net force acting on the person is zero. This means that the force exerted by the elevator is equal in magnitude and opposite in direction to the person's weight. Therefore, the person's weight is the same as their actual weight.
Weight during constant velocity = m * g
Substituting the given values:
Weight during constant velocity = 50 kg * 9.8 m/s^2
(c) Acceleration downward at 3 m/s^2:
During this stage, the person experiences a downward force greater than their weight due to the acceleration. Again, we can use the equation F = m * a to find the net force acting on the person.
The net force acting on the person can be found using the equation:
F_net = m * a
Weight during acceleration downward = m * (g - a)
Substituting the given values:
Weight during acceleration downward = 50 kg * (9.8 m/s^2 - 3 m/s^2)
By substituting the values and performing the calculations, you can find the person's weight during each stage of the lift ride.
(a) 3 m/s is not an acceleration rate.
You probably mean 3 m/s^2.
(b) Weight = M*g = 490 N
(c) 3 m/s is not a deceleration rate.