Chemistry

Cyclohexane has a freezing point of 6.6 degree Celsius and a K(f) of 20.0 degree Celsius/m. 1.50g of an unknown solute is dissolved wth 18.0g of cyclohexane. The freezing point of the solution was 1.3 degree Celsius Using this iInformation assuming the solute doesn't dissociate, calculate the:

a) The molality of this solution;

b) Moles of solute present;

c) Molar mass of the solute.

T = 6.6 - 1.3 = 5.3

5.3 = m x 20.0

molality = 5.3 / 20.0=0.265

moles solute = 0.265 x 0.0180 Kg =0.00477

molar mass solute = 1.50 / 0.00477=314.5 g/mol.

I think the answers may be right. I just want to make sure.

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  1. Looks ok to me.

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