a ship sends a snoar pulse of frequency 30kHz and duration 1.0 ms towards a submarine and receives a reflection of the pulse 3.2 s later. the speed of sound in water is 1500 ms-1. find the distance of the submarine from the wavelength of the pulse and the number of full waves emitted in the pulse.
2 * distance = V * t
no. of waves = frequency * (pulse duration)
because that distance includes there and back from the sub to the ship. so to only get the distance you have to divide by two. and ms means milli seconds so it is 0.001 seconds
i still don't get it. why is the distance x 2 and what does it mean ms for the pulse duration
Answer the above question
To find the distance of the submarine, we can use the formula:
Distance = Speed × Time
First, let's calculate the time it takes for the pulse to travel to the submarine and back. The pulse travels twice the distance between the ship and the submarine:
Total time = Time to the submarine + Time for the reflection = 2 × Time to the submarine
The time for the pulse to travel to the submarine can be found by dividing the round-trip time by 2:
Time to the submarine = Total time / 2 = 3.2 s / 2 = 1.6 s
Now, we can use the formula to calculate the distance:
Distance = Speed × Time
Distance = 1500 m/s × 1.6 s = 2400 meters
So, the distance of the submarine from the ship is 2400 meters.
Next, let's find the wavelength of the pulse. The formula for wavelength is:
Wavelength (λ) = Speed / Frequency
Using the given frequency of 30 kHz, we need to convert it to Hz:
Frequency = 30 kHz = 30,000 Hz
Now, we can calculate the wavelength:
Wavelength (λ) = Speed / Frequency
Wavelength (λ) = 1500 m/s / 30,000 Hz = 0.05 meters = 5 cm
Therefore, the wavelength of the pulse is 5 cm.
Finally, let's find the number of full waves emitted in the pulse. To do this, we can divide the duration of the pulse by the period of one wave:
Period = 1 / Frequency
Period = 1 / 30,000 Hz = 3.33 × 10^(-5) seconds
Number of waves = Duration / Period
Number of waves = 1.0 ms / (3.33 × 10^(-5) s) = 30,030 waves
Therefore, the number of full waves emitted in the pulse is 30,030 waves.