A baseball player hits a line drive. Just before the ball is struck, it is moving east at a speed of 38.8 m/s (87 mi/h). Just after contact with the bat, 1.05 10-3 s later, the ball is moving west at a speed of 46 m/s (103 mi/h). Find the ball's average acceleration.

Δp=p₂-(-p₁) = p₂ + p₁ = m(v₂+v₁),

F= Δp/Δt=ma ,
m(v₂+v₁)/Δt = ma,
a= (v₂+v₁)/Δt=
=(46+38)/1.05•10⁻³=8•10⁴ m/s²

change in velocity / change in time

(38.8 + 46) / .00105

To find the ball's average acceleration, we need to use the formula for average acceleration:

acceleration = (change in velocity) / (time interval)

In this case, the change in velocity is the difference between the initial velocity (moving east) and the final velocity (moving west). The time interval is given as 1.05 x 10^-3 seconds.

Let's calculate the change in velocity first:

change in velocity = final velocity - initial velocity
= (-46 m/s) - 38.8 m/s
= - 84.8 m/s

Now, we can calculate the average acceleration:

average acceleration = change in velocity / time interval
= (-84.8 m/s) / (1.05 x 10^-3 s)
≈ -80666.67 m/s^2

The ball's average acceleration is approximately -80666.67 m/s^2.

To find the ball's average acceleration, we can use the formula:

acceleration = (final velocity - initial velocity) / time.

First, let's convert the speeds from miles per hour to meters per second. We know that 1 mile is equal to 1609.34 meters and 1 hour is equal to 3600 seconds.

Initial velocity (east) = 38.8 m/s
Final velocity (west) = 46 m/s

Now, let's calculate the change in velocity:
change in velocity = final velocity - initial velocity = 46 m/s - (-38.8 m/s) = 84.8 m/s

The time taken for the change in velocity is given as 1.05 * 10^-3 s.

Now, we can substitute the values into the formula:

acceleration = (change in velocity) / time
acceleration = 84.8 m/s / (1.05 * 10^-3 s)
acceleration ≈ 80,761.9 m/s^2

The ball's average acceleration is approximately 80,761.9 m/s^2.