a stone of mass 50g is being rotated in circle of radius 50cm with a uniform speed of 2m/s.what is the acceleration of the stone?

Acceleration of an object in circular motion is:

magnitude = v²/r
v = 2 m/s
r = 0.5 m
Direction is towards the centre of the circle.

Mass is irrelevant (unless you need the force on the string).

I can't understand this

To find the acceleration of the stone, we first need to determine the centripetal acceleration. Centripetal acceleration is the acceleration experienced by an object moving in a circular path.

The formula for centripetal acceleration is:

a = v² / r

Where:
a = centripetal acceleration
v = velocity
r = radius

In this case, the velocity (v) is given as 2 m/s and the radius (r) is given as 50 cm. However, it's important to note that the unit of radius should be converted to meters before inserting the values into the formula.

1 meter = 100 centimeters

So, the radius in meters is:

r = 50 cm ÷ 100 cm/m = 0.5 m

Now, we can calculate the centripetal acceleration:

a = (2 m/s)² / 0.5 m
a = 4 m²/s² / 0.5 m
a = 8 m/s²

Therefore, the acceleration of the stone is 8 m/s².