A 45 foot long driveway goes uphill from the street to the garage of a house with a 5 degree angle of elevation. The garage must be _____ inches higher than the street. Round to the nearest whole number. (Watch the units!)

h = 45*sin5 = 3.92 Tt. = 47 In.

Thank You!!!!!!

To solve this problem, we need to find the vertical height between the street and the garage, given the length of the driveway and the angle of elevation.

First, convert the angle of elevation from degrees to radians. To do this, multiply the angle by π/180.

5 degrees * (π/180) ≈ 0.087 radians

Next, we can use trigonometry to find the vertical height. The vertical height can be calculated using the formula:

Vertical height = Length of the driveway * sin(angle of elevation)

Vertical height = 45 feet * sin(0.087 radians)

Now, use a calculator to find the sin(0.087 radians). The approximate value is 0.0015.

Vertical height ≈ 45 feet * 0.0015 ≈ 0.0675 feet

Since the question asks for the answer in inches, we need to convert the height from feet to inches. There are 12 inches in a foot, so:

Vertical height in inches ≈ 0.0675 feet * 12 inches/foot ≈ 0.81 inches

Rounding this to the nearest whole number, the garage must be approximately 1 inch higher than the street.