what is the molarity of 28.9 g of cacl2 dissolved in water to make 0.78 l of solution
0.33 M
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
First, you need to determine the amount of CaCl2 in moles. To do this, you divide the given mass of CaCl2 (28.9 g) by its molar mass (which you can find from the periodic table). The molar mass of CaCl2 is calculated as follows:
Ca: 1 * atomic mass of calcium (40.08 g/mol)
Cl: 2 * atomic mass of chlorine (35.45 g/mol)
Molar mass of CaCl2 = 40.08 g/mol + (2 * 35.45 g/mol) = 110.98 g/mol
Now, you can calculate the number of moles (n) of CaCl2:
n = mass / molar mass = 28.9 g / 110.98 g/mol
Next, you need to determine the volume of the solution in liters. The given volume is 0.78 L.
Finally, you can calculate the molarity (M) using the formula:
M = n / V
where M is the molarity, n is the number of moles of solute, and V is the volume of the solution in liters.
Plug in the values:
M = (28.9 g / 110.98 g/mol) / 0.78 L
Now you can calculate the molarity of the solution.
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You need to find and use the caps key on your keyboard.
mols CaCl2 = grams/molar mass
M = mols/L soln.